Rewrite the constant 3 as a logarithm with base 2:
x+1>0⟹x>-1x plus 1 is greater than 0 ⟹ x is greater than negative 1 Rewrite the constant 3 as a logarithm with
log0.5(x+1)≥log0.5(0.5-2)log base 0.5 of open paren x plus 1 close paren is greater than or equal to log base 0.5 of open paren 0.5 to the negative 2 power close paren Rewrite the constant 3 as a logarithm with
log0.5(x+1)≥-2log base 0.5 of open paren x plus 1 close paren is greater than or equal to negative 2 The argument must be positive: Rewrite the constant 3 as a logarithm with
Rewrite -2 as a logarithm with base 0.5:
Both arguments must be positive:
log2(2x−4)>log2(23)log base 2 of open paren 2 x minus 4 close paren is greater than log base 2 of open paren 2 cubed close paren