Let О”abcв€јо”def And Their Areas Be Respectively 64cmві And 121cmві. If Ef=15.4cm Find Bc. Apr 2026

BC=811×15.4cap B cap C equals 8 over 11 end-fraction cross 15.4 BC=8×1.4cap B cap C equals 8 cross 1.4 BC=11.2 cmcap B cap C equals 11.2 cm ✅ Final Answer The length of the corresponding side BCcap B cap C

import math area_abc = 64 area_def = 121 ef = 15.4 # Ratio of areas of similar triangles is equal to the square of the ratio of their corresponding sides. # (BC / EF)^2 = Area(ABC) / Area(DEF) # BC / EF = sqrt(Area(ABC) / Area(DEF)) bc = ef * math.sqrt(area_abc / area_def) print(f"{bc=}") Use code with caution. Copied to clipboard BC=811×15

Take the square root of both sides of the equation to find the ratio of the corresponding side lengths: Solve for side BCcap B cap C Multiply

811=BC15.48 over 11 end-fraction equals the fraction with numerator cap B cap C and denominator 15.4 end-fraction 4. Solve for side BCcap B cap C Multiply both sides by to isolate BCcap B cap C BC=811×15

The length of side BCcap B cap C 1. Identify the relationship between areas and sides

For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides. This relationship is expressed by the formula: